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Proof step 3 from proof min-two-01 (previous step)

a < b ⊦ b < a, (∅ ++ b ++ a).min = a

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ s ++ b ++ a = s ++ a ++ b

Rule argument

spec: set-basic inst: name: sw seq: ⊦ s ++ b ++ a = s ++ a ++ b subst: [b, a, s] → [a, b, ∅] flags: rewrite

Additional information

Used simplifier rules: min-two: ⊦ a < b → (∅ ++ a ++ b).min = a; Used terms: a, b, ∅