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Proof step 3 from proof minmax-02 (previous step)

s.min = s.max, s.max ∈ s ⊦ s.min < s.max, # s = 1, s = ∅, # s = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ 1 < # s → s.min < s.max

Rule argument

spec: oset inst: name: minmax-03 seq: ⊦ 1 < # s → s.min < s.max subst: [s] → [s] flags: rewrite, current

Additional information

Used simplifier rules: one-02: ⊦ m ≠ 0 → (¬ 1 < m ↔ m = 1); from specification nat-basic1 Used terms: s