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Proof step 1 from proof butmin-at (conclusion)

⊦ a ≠ st.min → st.butmin[a] = st[a]

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Butmin: ⊦ st.butmin = st -- st.min;%Del-at: ⊦ a ≠ b → (st -- b)[a] = st[a]; from specification store