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Proof step 1 from proof butmin-put-01 (conclusion)

⊦ a = st[a, d0].min ∧ ¬ a ∈ st → st[a, d].butmin = st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
a = st[a, d0].min ⊦ st[a, d] -- st[a, d].min = st, a ∈ st

Rule argument

Additional information

Used simplifier rules: Butmin: ⊦ st.butmin = st -- st.min;