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Proof step 1 from proof butmin-put (conclusion)

⊦ a = st.min ∧ ¬ a ∈ st → st[a, d].butmin = st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ st[st.min, d] -- st[st.min, d].min = st, st.min ∈ st

Rule argument

Additional information

Used simplifier rules: Butmin: ⊦ st.butmin = st -- st.min;