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Proof step 1 from proof butmin-rewput (conclusion)

⊦ a ≠ st[a, d].min → st[a, d].butmin = st.butmin[a, d]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ a = st[a, d].min, st[a, d] -- st[a, d].min = (st -- st.min)[a, d]

Rule argument

Additional information

Used simplifier rules: Butmin: ⊦ st.butmin = st -- st.min;