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Proof step 10 from proof butmin-rewput (previous step)

st[a, d].min ∈ st, st.min < st[a, d].min ⊦ st[a, d].min = st.min, a = st[a, d].min

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 11:
st[a, d].min ∈ st, st.min < st[a, d].min ⊦ st = ∅, st[a, d].min = st.min, a = st[a, d].min

Rule argument

fma: st = ∅

Additional information

Used simplifier rules: min: ⊦ (∅)[a, d].min = a; Used formulas: st = ∅