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Proof step 1 from proof size-del-01 (conclusion)

⊦ a ∈ st.keys → # (st -- a).keys = # st.keys - 1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: del-01: ⊦ a ∈ st.keys → (st -- a).keys = st.keys -- a;%del-size: ⊦ a ∈ s → #(s -- a) = # s - 1; from specification set-union