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Proof step 14 from proof changenonnxt-reachable (
previous step
)
ce.nxt = H[r1].nxt, (ce.nxt ' + x0).last ∈ H, path(ce.nxt ' + x0, H), r1 ∈ H, ∀ ce0, H0, r2, r3. ce0.nxt = H0[r2].nxt ∧ path(r3 ' + x0, H0) → path(r3 ' + x0, H0[r2, ce0]) ⊦ r1 = null, path(ce.nxt ' + x0, H[r1, ce])
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 5 terms: ce, H, r1, ce.nxt
Additional information
Used terms: ce, H, r1, ce.nxt