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Proof step 16 from proof changenonnxt-reachable (previous step)

ce.nxt = H[r1].nxt, (H[r].nxt ' + x0).last ∈ H, path(H[r].nxt ' + x0, H), r ∈ H, ∀ ce0, H0, r2, r3. ce0.nxt = H0[r2].nxt ∧ path(r3 ' + x0, H0) → path(r3 ' + x0, H0[r2, ce0]) ⊦ r = null, r = r1, path(H[r].nxt ' + x0, H[r1, ce])

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: ce, H, r1, H[r].nxt

Additional information

Used terms: ce, H, r1, H[r].nxt