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Proof step 27 from proof frommodified (previous step)

path(ce.nxt ' + x, H[r, ce]), ce.nxt ∈ H, x.last ∈ H ⊦ r = null, x = [], ce.nxt = null, r = x.last, ∃ x0. path(r ' + x0, H[r, ce]) ∧ (r ' + x0).last = x.last

User applied rule exists right

And closed the goal!

Rule argument

pos: right 5 terms: ce.nxt + x abort: F discard: T computed: F

Additional information

Used simplifier rules: path-cons: ⊦ path(r ' + r0 ' + x, H) ↔ ¬ ¬(r ∈ H ∧ r ≠ null ∧ H[r].nxt = r0 ∧ path(r0 ' + x, H));%c: ⊦ r + x0 = r ' + x0; from specification list[reflist]%a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist]%insin: ⊦ r ∈ H[r, ce]; from specification store[linheap]%At-same: ⊦ H[r, ce][r] = ce; from specification store[linheap]%lapp-02: ⊦ x0 ≠ [] → (r ' + x1 + x0).last = x0.last; from specification list-last[reflist] Used terms: ce.nxt + x