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Proof step 15 from proof k-reachable-def (previous step)

r ∈ H, H[r].nxt ∈ H ⊦ r = null, H[r].nxt = null, ∃ n. reachable-n(H, n, r, H[r].nxt)

User applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: 0 +1 abort: F discard: T computed: F

Additional information

Used simplifier rules: reachable-n-1: ⊦ reachable-n(H, 1, r, r0) ↔ reachable-1(H, r, r0);%reachable-1-def: ⊦ reachable-1(H, r, r0) ↔ r ≠ null ∧ r0 ≠ null ∧ r ∈ H ∧ r0 ∈ H ∧ H[r].nxt = r0; Used terms: 0 +1