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Proof step 33 from proof k-reachable-def (previous step)

H[r].nxt ∈ H, r ∈ H, reachable-n(H, n0, H[r].nxt, r0), ∀ r, H, r0. r ∈ H ∧ reachable-n(H, n0, r, r0) → n0 = 0 ∨ r = null ∨ (∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0) ⊦ H[r].nxt = null, r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

User applied rule all left

And obtained the following new goals

Proof step 34:
H[r].nxt ∈ H, r ∈ H, reachable-n(H, n0, H[r].nxt, r0), H[r].nxt ∈ H ∧ reachable-n(H, n0, H[r].nxt, r0) → n0 = 0 ∨ H[r].nxt = null ∨ (∃ x. path(H[r].nxt ' + x, H) ∧ (H[r].nxt ' + x).last = r0) ⊦ H[r].nxt = null, r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

Rule argument

pos: left 4 terms: H[r].nxt, H, r0 abort: F discard: T computed: T

Additional information

Used terms: H[r].nxt, H, r0