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Proof step 35 from proof k-reachable-def (previous step)

H[r].nxt ∈ H, r ∈ H, reachable-n(H, n0, H[r].nxt, r0), n0 = 0 ∨ path(H[r].nxt ' + x, H) ∧ (H[r].nxt ' + x).last = r0 ⊦ H[r].nxt = null, r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

User applied rule cut formula

And obtained the following new goals

Proof step 36:
n0 = 0, H[r].nxt ∈ H, r ∈ H, reachable-n(H, n0, H[r].nxt, r0), n0 = 0 ∨ path(H[r].nxt ' + x, H) ∧ (H[r].nxt ' + x).last = r0 ⊦ H[r].nxt = null, r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0
Proof step 38:
H[r].nxt ∈ H, r ∈ H, reachable-n(H, n0, H[r].nxt, r0), n0 = 0 ∨ path(H[r].nxt ' + x, H) ∧ (H[r].nxt ' + x).last = r0 ⊦ n0 = 0, H[r].nxt = null, r = null, ∃ x. path(r ' + x, H) ∧ (r ' + x).last = r0

Rule argument

fma: n0 = 0

Additional information

Used formulas: n0 = 0