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Proof step 9 from proof k-reachable-def (previous step)

r ∈ H ⊦ r = null, ∃ n. reachable-n(H, n, r, r)

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: 0 abort: F discard: T computed: F

Additional information

Used simplifier rules: reachable-n-base: ⊦ reachable-n(H, 0, r, r0) ↔ r = r0; Used terms: 0