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Proof step 10 from proof linearity-path (
previous step
)
path(H[r].nxt ' + x0, H), r ∈ H, ∀ r, H, y. path(r ' + x0, H) ∧ path(r ' + y, H) → x0 = y ∨ (∃ r0, y0. x0 = y + r0 ' + y0) ∨ (∃ r0, x1. y = x0 + r0 ' + x1) ⊦ r = null, ∃ r0, y. H[r].nxt ' + x0 = r0 ' + y
Heuristic quantifier closing applied rule exists right
And closed the goal!
Rule argument
pos: right 2 terms: H[r].nxt, x0
Additional information
Used terms: H[r].nxt, x0