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Proof step 4 from proof linearity-path (previous step)

path(r ' + y, H), r ∈ H ⊦ [] = y, r = null, ∃ r0, x. y = r0 ' + x

User applied rule constructor cut

And obtained the following new goals

Proof step 5:
y = r1 + y0, path(r ' + y, H), r ∈ H ⊦ [] = y, r = null, ∃ r0, x. y = r0 ' + x

Rule argument

var: y

Additional information

Used simplifier rules: reflist freely generated by [], +;;