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Proof step 1 from proof path-modify-strong (conclusion)

⊦ ¬ r0 ∈ x ∧ r0 ∈ H → (path(x + r1 ', H[r0, ce]) ↔ path(x + r1 ', H))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
r0 ∈ H ⊦ path(x + r1 ', H[r0, ce]) ↔ path(x + r1 ', H), r0 ∈ x

Rule argument

Additional information