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Proof step 1 from proof path-new-irrelevant-strong (conclusion)

⊦ ¬ r2 ∈ H ∧ ¬ r2 ∈ x ∧ r ∈ H → (path(r ' + x, H[r2, ce]) ↔ path(r ' + x, H))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
r ∈ H ⊦ path(r ' + x, H[r2, ce]) ↔ path(r ' + x, H), r2 ∈ x, r2 ∈ H

Rule argument

Additional information