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Proof step 4 from proof path-postfix (previous step)

path((r0 ' + x0) + r ' + y, H), ∀ r, y, H. path(x0 + r ' + y, H) → path(r ' + y, H) ⊦ path(r ' + y, H)

User applied rule all left

And obtained the following new goals

Proof step 5:
path((r0 ' + x0) + r ' + y, H), path(x0 + r ' + y, H) → path(r ' + y, H) ⊦ path(r ' + y, H)

Rule argument

pos: left 2 terms: r, y, H abort: F discard: T computed: T

Additional information

Used terms: r, y, H