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Proof step 29 from proof reach-n-path-n (previous step)

reachable-1(H, r, r1), reachable-1(H, r1, r2), reachable-1(H, r2, r3), reachable-n(H, n0, r3, r0), (∃ r6. reachable-1(H, r1, r6) ∧ (∃ r1. reachable-1(H, r6, r1) ∧ reachable-n(H, n0, r1, r0))) ↔ (∃ x. path(x, H) ∧ hd x = r1 ∧ x.last = r0 ∧ # x = 3 + n0) ⊦ ∃ x. path(x, H) ∧ hd x = r ∧ x.last = r0 ∧ # x = 4 + n0

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 5

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