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Proof step 36 from proof reach-n-path-n (previous step)

1 + # x1 = 3 + n0, reachable-1(H, r0, r4), reachable-1(H, r4, r5), reachable-n(H, n0, r5, (r0 ' + x1).last), path(r0 ' + x1, H), reachable-1(H, r, r0), reachable-1(H, r0, r2), reachable-1(H, r2, r3), reachable-n(H, n0, r3, (r0 ' + x1).last) ⊦ ∃ x. path(x, H) ∧ hd x = r ∧ x.last = (r0 ' + x1).last ∧ # x = 4 + n0

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 37:
x1 = [], 1 + # x1 = 3 + n0, reachable-1(H, r0, r4), reachable-1(H, r4, r5), reachable-n(H, n0, r5, (r0 ' + x1).last), path(r0 ' + x1, H), reachable-1(H, r, r0), reachable-1(H, r0, r2), reachable-1(H, r2, r3), reachable-n(H, n0, r3, (r0 ' + x1).last) ⊦ ∃ x. path(x, H) ∧ hd x = r ∧ x.last = (r0 ' + x1).last ∧ # x = 4 + n0
Proof step 38:
1 + # x1 = 3 + n0, reachable-1(H, r0, r4), reachable-1(H, r4, r5), reachable-n(H, n0, r5, (r0 ' + x1).last), path(r0 ' + x1, H), reachable-1(H, r, r0), reachable-1(H, r0, r2), reachable-1(H, r2, r3), reachable-n(H, n0, r3, (r0 ' + x1).last) ⊦ x1 = [], ∃ x. path(x, H) ∧ hd x = r ∧ x.last = (r0 ' + x1).last ∧ # x = 4 + n0

Rule argument

fma: x1 = []

Additional information

Used formulas: x1 = []