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Proof step 44 from proof reach-n-path-n (previous step)

∃ x. path(x, H) ∧ hd x = r ∧ x.last = r0 ∧ # x = 3 + n, ∀ H0, r1, r2. (∃ r3. reachable-1(H0, r1, r3) ∧ reachable-n(H0, n, r3, r2)) ↔ (∃ x. path(x, H0) ∧ hd x = r1 ∧ x.last = r2 ∧ # x = 2 + n) ⊦ ∃ r1. reachable-1(H, r, r1) ∧ (∃ r2. reachable-1(H, r1, r2) ∧ reachable-n(H, n, r2, r0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 45:
# x = 3 + n, path(x, H), ∀ H0, r1, r2. (∃ r3. reachable-1(H0, r1, r3) ∧ reachable-n(H0, n, r3, r2)) ↔ (∃ x. path(x, H0) ∧ hd x = r1 ∧ x.last = r2 ∧ # x = 2 + n) ⊦ ∃ r1. reachable-1(H, hd x, r1) ∧ (∃ r2. reachable-1(H, r1, r2) ∧ reachable-n(H, n, r2, x.last))

Proof step 44 from proof reach-n-path-n (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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