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Proof step 2 from proof reach-n-split (previous step)

n = n0 + m ∧ m ≤ n, reachable-n(H, n, r, r0), m < n ⊦ ∃ r1. reachable-n(H, m, r, r1) ∧ reachable-n(H, n0, r1, r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
reachable-n(H, n0 + m, r, r0) ⊦ n0 = 0, ∃ r1. reachable-n(H, m, r, r1) ∧ reachable-n(H, n0, r1, r0)

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%l-01: ⊦ m < m + n ↔ n ≠ 0; from specification nat-basic2%lels-03: ⊦ m < n → m ≤ n; from specification nat