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Proof step 14 from proof reach-reachnext (previous step)

(H[r].nxt ' + x0).last ∈ H, path(H[r].nxt ' + x0, H), r ∈ H, H[(H[r].nxt ' + x0).last].nxt ∈ H, ∀ H0, r1. H0[(r1 ' + x0).last].nxt ∈ H0 ∧ path(r1 ' + x0, H0) → H0[(r1 ' + x0).last].nxt = null ∨ path(r1 ' + x0 + H0[(r1 ' + x0).last].nxt ', H0) ⊦ r = null, H[(H[r].nxt ' + x0).last].nxt = null, path(H[r].nxt ' + x0 + H[(H[r].nxt ' + x0).last].nxt ', H)

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: H, H[r].nxt

Additional information

Used simplifier rules: a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist] Used terms: H, H[r].nxt