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Proof step 6 from proof reachable-n-rec-rev (previous step)

reachable-n(H, n, r, r1) ∧ reachable-1(H, r1, r0) ⊦ reachable-n(H, n + 1, r, r0), reachable-n(H, n + 1, r, r0) ∧ n < n + 1

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: reachable-n-trans seq: ⊦ reachable-n(H, n, r, r0) ∧ reachable-n(H, n0, r0, r1) → (¬ reachable-n(H, n + n0, r, r1) ↔ false) subst: [H, n, r, r0, n0, r1] → [H, n, r, r1, 1, r0] flags: current, []

Additional information

Used simplifier rules: reachable-1-def: ⊦ reachable-1(H, r, r0) ↔ r ≠ null ∧ r0 ≠ null ∧ r ∈ H ∧ r0 ∈ H ∧ H[r].nxt = r0;%reachable-n-rec: ⊦ reachable-n(H, n + 1, r, r0) ↔ (∃ r1. reachable-1(H, r, r1) ∧ reachable-n(H, n, r1, r0));%reachable-n-1: ⊦ reachable-n(H, 1, r, r0) ↔ reachable-1(H, r, r0);%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: H, n, r, r1, 1, r0