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Proof step 3 from proof reachable-n-rec2 (previous step)

reachable-n(H, 1 + 1, r, r0) ↔ (∃ r1. reachable-1(H, r, r1) ∧ reachable-n(H, 1, r1, r0)) ⊦ reachable-n(H, 2, r, r0) ↔ reachable-1(H, r, H[r].nxt) ∧ reachable-1(H, H[r].nxt, r0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
reachable-n(H, 2, r, r0) ↔ (∃ r1. reachable-1(H, r, r1) ∧ reachable-1(H, r1, r0)) ⊦ reachable-n(H, 2, r, r0) ↔ reachable-1(H, r, H[r].nxt) ∧ reachable-1(H, H[r].nxt, r0)

Rule argument

Additional information

Used simplifier rules: reachable-n-1: ⊦ reachable-n(H, 1, r, r0) ↔ reachable-1(H, r, r0);%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2