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Proof step 6 from proof reachable-n-trans (previous step)

H[r].nxt ∈ H, r ∈ H, reachable-n(H, n0, r0, r1), reachable-n(H, n1, H[r].nxt, r0), reachable-n(H, n1 + n0, H[r].nxt, r1) ⊦ r = null, H[r].nxt = null, ∃ r2. reachable-1(H, r, r2) ∧ reachable-n(H, n1 + n0, r2, r1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: H[r].nxt

Additional information

Used simplifier rules: reachable-1-def: ⊦ reachable-1(H, r, r0) ↔ r ≠ null ∧ r0 ≠ null ∧ r ∈ H ∧ r0 ∈ H ∧ H[r].nxt = r0; Used terms: H[r].nxt