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Proof step 3 from proof reachable-split-last (previous step)

reachable(r, r0, H) ⊦ ∃ r1. reachable(r, r1, H) ∧ H[r1].nxt = r0 ∧ H[r1].nxt ∈ H ∧ H[r1].nxt ≠ null, r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
reachable(r, r0, H), r0 ∈ H ⊦ r = r0, ∃ r1. reachable(r, r1, H) ∧ H[r1].nxt = r0 ∧ H[r1].nxt ≠ null

Rule argument

Additional information

Used simplifier rules: reachable-notnullinH: ⊦ reachable(r, r1, H) → (¬ r1 ∈ H ↔ false);%reach-alloc: ⊦ reachable(r, r1, H) → r1 ∈ H;