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Proof step 114 from proof rem-stays-reachable-aux2 (previous step)

(r0 ' + x0).last = (r ' + x1).last, H[r0].nxt = (r2 ' + x2).last, (r ' + x1).last = (r ' + x1 + (r2 ' + x2).butlast).last, path(r0 ' + x0, H), r0 ∈ H, H[r0].nxt ∈ H, path(r ' + x1 + r2 ' + x2 + r0 ', H), path(r ' + x1 + r2 ' + x2, H), path(r ' + x1, H), (r ' + x1).last ∈ H, H[r0].nxt ∈ x1 ∨ H[r0].nxt = r2 ∨ H[r0].nxt ∈ x2 ⊦ r2 = r0, r = r2, r0 = r, H[r0].nxt = null, dups(x2), dups(x1), dups(x1 + x2), r0 ∈ x2, r0 ∈ x1, r2 ∈ x2, r2 ∈ x1, r ∈ x2, r ∈ x1, dups(x0), r0 ∈ x0, r0 ∈ (r2 ' + x2).butlast

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: list-last inst: reflist name: bapp seq: ⊦ x0 ≠ [] → (x1 + x0).butlast = x1 + x0.butlast subst: [x0, x1] → [x2, r2 '] flags: rewrite

Additional information

Used terms: x2, r2 '