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Proof step 197 from proof rem-stays-reachable-aux2 (previous step)

H[r0].nxt = H[r1].nxt, path(H[H[r1].nxt].nxt ' + x + r0 ', H), path(H[H[r1].nxt].nxt ' + x3 + r1 ', H), H[r1].nxt ∈ H, r0 ∈ H, path(r ' + x1 + r0 ', H), path(r ' + (x1 + r0 ') + H[r1].nxt ' + (H[H[r1].nxt].nxt ' + x3) + r1 ', H), r1 ∈ H ⊦ H[r1].nxt = null, r = H[H[r1].nxt].nxt, H[r1].nxt = H[H[r1].nxt].nxt, r1 = H[H[r1].nxt].nxt, r1 = r, r = H[r1].nxt, H[r1].nxt = r1, H[H[r1].nxt].nxt = r0, r1 = r0, r = r0, r1 = null, r1 ∈ x, r0 ∈ x, H[r1].nxt ∈ x, dups(x), H[H[r1].nxt].nxt ∈ x, r ∈ x1, r ∈ x3, H[r1].nxt ∈ x1, dups(x1), dups(x3), H[r1].nxt ∈ x3, r1 ∈ x3, r0 ∈ x1, r0 ∈ x3, dups(x1 + x3), H[H[r1].nxt].nxt ∈ x1, H[H[r1].nxt].nxt ∈ x3, r1 ∈ x1

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: inst: name: linearity-path seq: path(r ' + x, H), path(r ' + y, H) ⊦ x = y ∨ (∃ r0, y0. x = y + r0 ' + y0) ∨ (∃ r0, x0. y = x + r0 ' + x0) subst: [r, x, H, y] → [H[H[r1].nxt].nxt, x3 + r1 ', H, x + r0 '] flags: current, []

Additional information

Used simplifier rules: neq-03: ⊦ ¬ r ∈ x ∧ r ≠ r0 → x + r0 ' ≠ x0 + r ' + x1; from specification list[reflist]%a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist]%app-06: ⊦ x0 + r ' = x1 + r0 ' ↔ x0 = x1 ∧ r = r0; from specification list[reflist] Used terms: H[H[r1].nxt].nxt, x3 + r1 ', H, x + r0 '