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Proof step 23 from proof rtc+-unfold-last (previous step)

rtc(n, a, c), p(c, b) ⊦ ∃ n. n ≠ 0 ∧ rtc(n, a, b)

User applied rule exists right

And obtained the following new goals

Proof step 24:
rtc(n, a, c), p(c, b) ⊦ n + 1 ≠ 0 ∧ rtc(n + 1, a, b)

Rule argument

pos: right 1 terms: n + 1 abort: F discard: T computed: F

Additional information

Used terms: n + 1