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Proof step 31 from proof rtc+-unfold-last (previous step)

p(c, b), p(a, c0), rtc(n0, c0, c), p(c0, c1), rtc(n0, c1, b), ∀ a, c, b. rtc(n0, a, c) ∧ p(c, b) → (∃ c. p(a, c) ∧ rtc(n0, c, b)) ⊦ ∃ c1. p(a, c1) ∧ (∃ c. p(c1, c) ∧ rtc(n0, c, b)), ∃ c. p(c0, c) ∧ rtc(n0, c, b)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: c1

Additional information

Used terms: c1