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Proof step 9 from proof rtc+-unfold (previous step)

p(a, c), rtc(n0, c, b) ⊦ p*(c, b), ∃ c. p(a, c) ∧ p*(c, b)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b))
Proof step 11:
p(a, c), rtc(n0, c, b) ⊦ ∃ n. rtc(n, c, b), ∃ c. p(a, c) ∧ p*(c, b)

Rule argument

spec: inst: name: rtc seq: ⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b)) subst: [b, a] → [b, c] flags: rewrite, current

Additional information

Used terms: b, c