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Proof step 1 from proof rtc-refl (conclusion)

⊦ p*(a, a)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b))
Proof step 3:
⊦ ∃ n. rtc(n, a, a)

Rule argument

spec: inst: name: rtc seq: ⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b)) subst: [b, a] → [a, a] flags: rewrite, current

Additional information

Used terms: a, a