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Proof step 8 from proof rtc-trans (
previous step
)
p*(b, c), p(a, c0), rtc(n0, c0, b), rtc(n0, c0, b) ∧ p*(b, c) → p*(c0, c) ⊦ p*(a, c)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
p*(b, c), p(a, c0), rtc(n0, c0, b), p*(c0, c) ⊦ p*(a, c)
Rule argument
Additional information