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Proof step 1 from proof rtc-unfold (conclusion)

⊦ p*(a, b) ↔ a = b ∨ p+(a, b)

User applied rule case distinction

And obtained the following new goals

Proof step 2:
p*(a, b) ⊦ a = b ∨ p+(a, b)
Proof step 9:
a = b ∨ p+(a, b) ⊦ p*(a, b)

Rule argument

pos: right 1

Additional information