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Proof step 5 from proof rtc-unfold (previous step)

p*(a, b) ⊦ a = b, ∃ n. n ≠ 0 ∧ rtc(n, a, b)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b))
Proof step 7:
∃ n. rtc(n, a, b) ⊦ a = b, ∃ n. n ≠ 0 ∧ rtc(n, a, b)

Rule argument

spec: inst: name: rtc seq: ⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b)) subst: [b, a] → [b, a] flags: rewrite, current

Additional information

Used terms: b, a