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Proof step 8 from proof rtc-unfold (previous step)

rtc(n, a, b) ⊦ a = b, ∃ n. n ≠ 0 ∧ rtc(n, a, b)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: n

Additional information

Used simplifier rules: rtc-base: ⊦ rtc(0, a, b) ↔ a = b; Used terms: n