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Proof step 13 from proof rtc-last (previous step)

∃ c. rtc(m, Pelem)(a, c) ∧ Pelem(c, b) ⊦ ∃ c. Pelem(a, c) ∧ rtc(m, Pelem)(c, b)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information