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Proof step 1 from proof addthree (conclusion)

⊦ s ++ a ++ b ++ c ++ a = s ++ a ++ b ++ c

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: eq-03: ⊦ s ++ a = s ↔ a ∈ s;%add: ⊦ ¬ a ∈ s ++ b ↔ a ≠ b ∧ ¬ a ∈ s;%rax: ⊦ a ∈ s ++ b ↔ ¬ ¬(a = b ∨ a ∈ s);