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Proof step 1 from proof eqtwo (conclusion)

⊦ ∅ ++ a ++ b = ∅ ++ a ++ c ↔ b = c

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: in-05: ⊦ s ++ a = s0 ++ b ∧ a ≠ b → a ∈ s0;%eq: ⊦ a ∈ s → s ++ a = s;%in-04: ⊦ a ∈ ∅ ++ b ↔ a = b;