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Proof step 2 from proof size-one-03 (
previous step
)
# s = 1 ⊦ ∃ a. s = ∅ ++ a
User applied rule insert lemma
And obtained the following new goals
Proof step 3
:
⊦ # s = 1 → (∃ a. s = ∅ ++ a)
Rule argument
spec: set-basic inst: name: size-one seq: ⊦ # s = 1 → (∃ a. s = ∅ ++ a) subst: [s] → [s] flags: current, []
Additional information
Used terms: s