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Proof step 6 from proof Data-in-putdelput (previous step)

a0 ∈ st ⊦ a0 = a, a0 = b, a0 = c, st[a0] = d1, st[a0] = d2, ∃ a1. a1 ∈ st ∧ st[a1] = st[a0]

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 6 terms: a0

Additional information

Used terms: a0