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Proof step 1 from proof Data-in-puteq (conclusion)

⊦ d0 = d1 → d0 ∈ st[a, d1]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ ∃ a0. a0 ∈ st[a, d1] ∧ st[a, d1][a0] = d1

Rule argument

Additional information

Used simplifier rules: Data-in: ⊦ d ∈ st ↔ (∃ a. a ∈ st ∧ st[a] = d);