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Proof step 1 from proof Diff-rec-rev (conclusion)

⊦ st \ (s ++ a) = (st -- a) \ s

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Diff-rec: ⊦ st \ (s ++ a) = (st \ s) -- a;%Diff-del-rw: ⊦ (st -- a) \ s = (st \ s) -- a;