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Proof step 3 from proof In-data-in (
previous step
)
a ∈ st ⊦ ∃ a0. a0 ∈ st ∧ st[a0] = st[a]
Heuristic quantifier closing applied rule exists right
And closed the goal!
Rule argument
pos: right 1 terms: a
Additional information
Used terms: a