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Proof step 1 from proof dom-isemp (conclusion)
⊦ dom st = ∅ ↔ st = ∅
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2)
Proof step 3
:
⊦ (∀ a. a ∈ dom st ↔ a ∈ ∅) ↔ st = ∅
Rule argument
spec: set-basic inst: name: Extension seq: ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) subst: [s2, s1] → [∅, dom st] flags: rewrite
Additional information
Used terms: ∅, dom st