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Proof step 4 from proof rem-write (
previous step
)
⊦ ∀ a0. (a0 ∈ st[a, d] \ s ↔ a0 ∈ (st \ s)[a, d]) ∧ (st[a, d] \ s)[a0] = (st \ s)[a, d][a0], a ∈ s
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
⊦ a ∈ s, (a0 ∈ st[a, d] \ s ↔ a0 ∈ (st \ s)[a, d]) ∧ (st[a, d] \ s)[a0] = (st \ s)[a, d][a0]
Rule argument
Additional information