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Proof step 1 from proof Del-other-data (conclusion)

⊦ st[a] ≠ st[b] → (a ∈ st -- b ↔ a ∈ st)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Del-in: ⊦ a ∈ st -- b ↔ a ≠ b ∧ a ∈ st;%notmemlookup: ⊦ ¬ a ∈ st → st[a] = (∅)[a];